4! = 4*3*2*1 = 24
This can be done with a reverse for loop like this:
public double calcfactor(int number)
{
if (number == 0) return 1;
double factorial = 1;
for(int i = number; i>=1; i--)
{
Console.WriteLine(factorial = factorial*i);
}
return factorial;
}
But it can also be solved like this with a recursive method call:
4! = 4* (4-1) *(4-2)*(4-3) = 24
But be careful to break out of the loop with some condition.
public double calcfactor(int number)
{
if (number == 0) return 1;
return number * calcfactor(number - 1);
}